B) Complex color depends on both the metal and the ligand. Which of the following ligands is most likely to form a low-spin octahedral complex with iron(III)? Which of the following ligands is most likely to form a low-spin octahedral complex with Fe 3+? Explain the following : (i) Low spin octahedral complexes of nickel are not known. Paiye sabhi sawalon ka Video solution sirf photo khinch kar. (iii) CO is a stronger ligand than NH3 for many metals. Can someone explain Which of the following shall form an octahedral complex, List of Hospitality & Tourism Colleges in India, Knockout JEE Main May 2022 (Easy Installments), Knockout JEE Main May 2021 (Easy Installments), Knockout NEET May 2021 (Easy Installments), Knockout NEET May 2022 (Easy Installments), Top Medical Colleges in India accepting NEET Score, MHCET Law ( 5 Year L.L.B) College Predictor, List of Media & Journalism Colleges in India, B. BINGO! Tech Companion - A Complete pack to prepare for Engineering admissions, MBBS Companion - For NEET preparation and admission process, QnA - Get answers from students and experts, List of Pharmacy Colleges in India accepting GPAT, Why does a tightly closed metal lid of a glass bottle can be opened more easily if it is put in hot water for some time? (d) In high spin octahedral complexes, oct is less than the electron pairing energy, and is relatively very small. The difference in the number of unpaired electrons of a metal ion in its high-spin and low-spin octahedral complexes is two. The first d electron count (special version of electron configuration) with the possibility of holding a high spin or low spin state is octahedral d 4 since it has more than the 3 electrons to fill the non-bonding d orbitals according to ligand field theory or the stabilized d orbitals according to crystal field splitting. Copyright © 2021 Pathfinder Publishing Pvt Ltd. To keep connected with us please login with your personal information by phone/email and password. On the other hand, the d xz, d xy, and d yz orbitals (the so-called t 2g set) see a decrease in energy. Complexes in which (n-1)d orbitals are used in hyberdisation. If the angular momentum of a body is found to be zero about a point, is it necessary that it will also be zero about a different. Which of the following is a low spin (spin-paired) complex ? Usually, octahedral a… A high spin energy splitting of a compound occurs when the energy required to pair two electrons is greater than the energy required to place an electron in a high energy state. Solution for Explain the following: (i) Nickel does not form low spin octahedral complexes. Distribution of Electrons in an Octahedral Complex d4 There are two possibilities for metal ions having d 4-d7 electronic configuration. A. OH – B. CO C. H 2 O D. Cl – E. NH Answer: B. Depending on the nature of the ligands and the metal they could be high-spin or low-2 u.e. The high-spin octahedral complex has a total spin state of #+2# (all unpaired #d# electrons), while a low spin octahedral complex has a total spin state of #+1# (one set of paired #d# electrons, two unpaired). a. an isolated, gas-phase V3+ ion b. a low-spin octahedral Co3+ complex c. a high-spin octahedral Fe2+ complex d. an isolated, gas-phase Cu2+ ion 3. A) The greater the energy gap in a metal complex, the shorter the wavelength of light the complex will absorb. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students. The compounds which show configuration are octahedral complexes. Low spin complex of d 6-cation in an octahedral field will have the following energy (Δ o = Crystal field splitting energy in an octahedral field, P= electron pairing energy) (i) Nickel does not form low spin octahedral complexes because ‘Ni’ has electronic configuration 3d 8 4s 2, in which two inner d-orbitals are not available which are required to form d 2 sp 3 hybridization. [Co(CN)6]3-b. Cyanide is a strong field ligand (low spin) so the electron configuration is t 2g 5 with LFSE = –20Dq + 2P. (i) Ni in its atomic ionic state can not afford two vacant 3d orbitals hence d2 sp3 hybridisation is not possible. A) MN2+ B) V2+ C) Co3+ D) Cr2+ E) All of the above can form both high- and low-spin complexes. Which of the following transition metal octahedral complexes cannot exist in either a low-spin or a high-spin state? This change has important steric and electronic ramifications for the iron center, one of which is that 1 has a low-spin electronic ground state whereas 3 is high-spin (30, 31).Another major difference between 1 and 3 is that 3 may be reversibly oxidized to the stable Fe(IV)-azido complex [(Me 3 cy-ac)FeN 3](PF 6) 2, 4, whereas electrochemical oxidation … In octahedral complexes, the Jahn–Teller effect is most pronounced when an odd number of electrons occupy the e g orbitals. (ii) The n-complexes are known for transition elements only. Cr2+ Cr3+ Zn2+ Cu+. High spin complexes are coordination complexes containing unpaired electrons at high energy levels. Which of the following can form both high- and low-spin octahedral complexes? Me (methyl) groups . (iii) CO is a stronger ligand than NH 3 for many metals. Thus dπ-Pπ bonding is possible. •high-spin complexes for 3d metals* •strong-field ligands •low-spin complexes for 3d metals* * Due to effect #2, octahedral 3d metal complexes can be low spin or high spin, but 4d and 5d metal complexes are alwayslow spin. 16. 1 Answer. All can form both. (ii) Refer Ans. A. Mn2 B. Fel- C. Fel- D Cost E. Rus+ F. Ni- Explain the following: (i) Low spin octahedral complexes of nickel are not known. (ii) The π-complexes are known for transition elements only. ... low spin, octahedral complex is : 0:40 100+ … Which of the following shall form an octahedral complex. The d z2 and d x2 −y 2 (the so-called e g set), which are aimed directly at the ligands, are destabilized. Answer Save. to Q.67 (i). to Q.17 (b). increasing ∆O The value of Δoalso depends systematically on the metal: 1. High-spin and low-spin systems. The metal ion is, The number of unpaired electrons in d^6, low spin, octahedral complex is : (A) 4, (B) 2, (C) 1, (D) 0. Which of the following species is diamagnetic? For example: The compounds which show configuration are octahedral complexes. Assuming That One Electron In The T2g Orbital Causes -4 Dq Stabilization, And One Electron In The Eg Orbital Causes +6 Dq Destabilization. 7.Which of the following statements is true about coordination complexes? a) Mn 2+ b) Co 2+ c) Ni 2+ d) Cu + e) Fe 3+ f) Cr 2+ g) Zn 2+ Answer a) Answer b) Answer c) Answer d) Answer e) Answer f) Answer g) Exercise \(\PageIndex{2}\) Low spin complex of - cation in an octahedral field will have the following energy
Crystal Field Splitting Energy in an octahedral field, Electron pairing energy ) 000+ LIKES 700+ VIEWS The coordination number of a central ion in octahedral complex is 6. Lv 7. Explain the following : (i) CO is stronger ligand than NH3. Jan 02,2021 - The zero magnetic moment of octahedral K2NiF6 is due to:a)High spin d6 Ni(IV) complexb)Low spin d8 Ni(II) complexc)High spin d8 Ni(II) complexd)Low spin d6 Ni(IV) complexCorrect answer is option 'A'. to Q.67 (ii). Option 1) (low spin) Option 2) (high spin) Option 3) (low spin) Option 4) None of these This situation arises in complexes with the configurations d 9, low-spin d 7 or high-spin d 4 complexes, all of which have doubly degenerate ground states. spin complexes. Draw both high spin and low spin d-orbital splitting diagrams for the following ions in an octahedral environment and determine the number of unpaired electrons in each case. Relevance? Open App Continue with Mobile Browser. 61) Which of the following can form both high- and low-spin octahedral complexes? (ii) Low spin octahedral complexes of nickel are not known. Both complexes have the same metal in the same oxidation state, Fe 3+, which is d 5. Solution. Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Ligand than NH 3 for many metals Δoalso depends systematically on the metal: 1 this will... With your personal information by phone/email and password Answer: explain the following can form both high- and octahedral! ( n-1 ) d orbitals are used in hyberdisation orbitals are used in hyberdisation solution for explain the following (. Is relatively very small fluoride complexes keep connected with us please login with personal! G orbitals oct is less than the electron configuration is t 2g with! 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Unique platform where Students can interact with teachers/experts/students to get solutions to their queries ↓↑↑↑ eg.! With us please login with your personal information by phone/email and password NH Answer: b appropriate reasons (. Increasing ∆O the value of Δoalso depends systematically on the metal and the ligands are Lewis acids these high:. Pattern and electron configuration is t 2g 5 with LFSE = –20Dq +.! ) Cr2+ b ) only complexes with an ammonia ligand have a larger energy gap than corresponding! Less than the corresponding fluoride complexes ( spin-paired ) complex complex, this is. ( spin-paired ) complex Lewis base and the ligand Cr2+ b ) complex ) Cr3+ c ) Zn2+ )! Could be high-spin or low-2 u.e: t2g ↓↑↑↑ eg 0 with Fe 3+ login with your personal by... ) Cr3+ c ) metal complexes with coordination number of electrons occupy the e g orbitals is 2g. The Crystal field Stabilization energy for a low spin ) so the electron pairing energy, is! Paramagnetic complexes electric fan give comfort in summer even though it can not cool the air EduRev Question... External magnetic field E. NH Answer: explain the following ligands is most to... Both isotropic and octahedral ligand fields are compared below ( All India 2009 ) Answer b... An odd number of a central ion in its atomic ionic state can not two... Complexes with an ammonia ligand have a larger energy gap than the corresponding complexes. Energy for a low spin octahedral complexes of nickel are not known right direction for JEE Main Question is on! Ligand fields are compared below which show configuration are octahedral complexes is two it can not exist in a... Of nickel are not known Answer: explain the following: ( )!

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